F - String Avin has a string. He would like to uniform-randomly select four characters (selecting the same character is allowed) from it. You are asked to calculate the probability of the four characters being ”avin” in order. Input The first line contai…

K - Class Avin has two integers a, b (1 ≤ a, b ≤ 1, 000). Given x a b and y a - b, can you calculate a*b? Input The first line contains two integers x, y. Output Print the result of a*b. Sample Input 4 2 Sample Output 3 题目大意：这道题连我…

HPU简介 HPU是一个DB2工具，能在线快速卸载数据到文件，或其他BigData环境。在DB2数据库保护及业务数据保护的的某些场景下，可以使用此工具快速备份恢复。 DB2 保护场景 1.硬件或软件级别异常保护：如硬件级别高可用、HADR、QRepl…

题目链接&#xff1a;http://pipakaca.com/problem.php?cid1037&pid9 这也是道经典的DP问题。 其中如果每次可以走x个台阶&#xff0c;分两种情况 1&#xff1a;i>x:dp[i]dp[i-1]dp[i-2]...dp[i-x] 2&#xff1a;i<x&#xff1a;dp[i]dp[i-1]dp[i-2]...dp[0] 代…

#include<stdio.h> int main() { int d[55]; d[0] 0; d[1] 1; for (int i 2 ; i < 50 ; i) { d[i] d[i-1] d[i-2]; } int n; scanf ("%d",&n); printf ("%d",d[n]); return 0; }

点击打开链接 /* np 正数个数 nm 负数个数 Min 记录绝对值最小的数字 s 记录所有数字的和 */ #include<cstdio> int main() {int n,t,a,np,nm,Min,s,m;scanf("%d",&t);while(t--){scanf("%d",&n); Min10000000001103,npnms0;m2*n-1;while(m…

1152: 棋盘变换 [搜索] 时间限制: 1 Sec 内存限制: 128 MB 题目描述 给定一个4*4的01棋盘&#xff0c;1代表棋子&#xff0c;0代表空格&#xff0c;棋子1每次可以移动到相邻上下左右四个位置的空格。然后再给定你目标棋盘&#xff0c;问你最少在多少步能把当前棋盘变成目标棋…

D - 绝对值排序 HDU - 2020 #include<stdio.h> #include<math.h> int main() { int a[105]; int i,j,b,t; while(scanf("%d",&b)&&b) { for(i0;i<b;i)scanf("%d",&a[i]); for(i0;i<b;i)for(ji1;j<b;j)if(abs(a[…